# 12V Fan Directly on 220V AC

Posted on Feb 5, 2014

This circuit idea is certainly not new, but when it comes to making a trade-of between using a small, short-circuit proof transformer or a capacitive voltage divider (directly from 230 V mains voltage) as the power supply for a fan, it can come in very handy. If forced cooling is an afterthought and the available options are limited then perhaps t

here is no other choice. At low currents a capacitive divider requires less space than a small, short-circuit proof transformer. R1 and R2 are added to limit the inrush current into power supply capacitor C2 when switching on. Because the maximum rated operating voltage of resistors on hand is often not known, we choose to have two resistors for the current limit. The same is true for the discharge resistors R3 and R4 for C1. If the circuit is connected to a mains plug then it is not allowed that a dangerous voltage remains on the plug, hence R3 and R4. Capacitor C1 determines the maximum current that can be supplied. Above that maximum the power supply acts as a current source. If the current is less then zener diode D1 limits the maximum voltage and dissipates the remainder of the power. It is best to choose the value of C1 based in the maximum expected current. As a rule of thumb, start with the mains voltage - when calculating C1. The 12 V output voltage, the diode forward voltage drops in B1 and the voltage drop across R1 and R2 can be neglected for simplicity. The calculated value is then rounded to the nearest E-12 value. The impedance of the capacitor at 50 Hz is 1 / (2p50C). If, for example, we want to be able to supply 50 mA, then the required impedance is 4600 (230 V/50 mA). The value for the capacitor is then 692 nF. This then becomes 680 nF when rounded. To compensate for mains voltage variations and the...

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