Door lock Motor

The measured resistance of door lock motor was about 2 ohm. Therefore, supplying 5V, the current becomes 5v/2ohm= 2. 5A. Regarding that the peak output current of L293B is 2A, the current flowing inside the motor is slightly over 2A, but it does not occur any problem because the motor will be used just for several seconds. Voltage regulator (LM7805

) was used to regulate the voltage from 14V to 5V. 7805`s peak output current is 2. 5A when the voltage difference between the input and the output is 9V (14-5=9V). Therefore 7805 can supply enough current for door lock motor.

Leave Comment

characters left:

New Circuits