Reading a voltage divider schematic

Ground is used as a reference for the voltage divider, and that each successive point above ground is how much voltage is dropped across the circuit. (So with a 15 volt input, and 5K ohm for each resistor the taps would be 5, 10, and 15 volts respectively. ) What I do not understand is by placing ground at that location, wouldn`t you immediately sink all the current to ground and have nothing
Reading a voltage divider schematic - schematic

moving through the voltage divider As I understand it, current will move to either ground or a more positively charged location (such as the positive side of a battery in this case), but with ground located where it is I do not understand why all current would not immediately sink to ground vice the voltage divider. Please let me know if this is just a poorly developed example or where my misunderstanding is.

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