new pedal schematic


Posted on Feb 5, 2014

U1 (555 in monostable) creates a square wave signal to matchyour signal. then it sends that square wave into the mixer (u2) along with your original signal to be mixed. so it actually is a doubler. every note you play will have a square wave note of the same pitch right beside it! the two pitches, the original and the square wave are mixable this pedal makes a note of the same pitch,


new pedal schematic
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in square wave. it plays along with your notes. it has 2 potentiometers in there to control how loud each is. basically, you get a square wave note and your original note Interesting circuit, but I don`t think its going to work the way you think. The output frequency will be fixed, and will be determined by the value you select for r1 and c1. Lets say you pluck the A string. That will be 110hz. You`ll trigger the 555 110 times per second, but the output will always be a set frequency. If you set r1/c1 to be to large, the output will still be cycling when the new input pulse arrives. You`ll get some staccato chirps. Here`s another way to approach this. Bring the input into an opamp, then have the opamp output go to two flip-flops. One positive edge triggered, the other negative edge triggered. Mix the two outputs using another opamp. One FF generates the positive half of the waveform, and the other FF generates the negative half. That way, you`ll track the input frquency better. Edit: Btw, I wasn`t clear there. You`ld use the dual FF circuit to generate double the input frequency. For the same frequency squarewave, you`ld just run the input into an opamp configured as a differentiator.




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