10 Bit A-D converter circuit

Posted on Aug 10, 2012

Each time a pulse is applied to the conversion of the control input, Ql resets the 1000 pF capacitor to 0 V. This action takes 200 ns to reset the falling edge of the convert command pulse, the capacitor begins to charge linearly. In exactly 10 microseconds, it loads to 2.5 V. The ramp is 10 microseconds applied to the positive input of the LTl016. The LT1016 compares the ramp Ex, the unknown, its negative input. For a 0 V - 2.5 V range, Ex is applied to the resistance of 2.5 k ohm.

10 Bit A-D converter circuit - image 1
Click here to download the full size of the above Image.

On a 0 V - 10 V, 2.5 k ohm resistor is grounded, and Ex is applied to the resistance of 7.5 k ohm. LT1016 output is a pulse whose width is directly dependent on the value of Ex. This pulse width is used at the gate a clock at 100 MHz. The 100 MHz clock pulse bursts that appear at the output is proportional to Eg for a 0 V - 10 V input, 1024 pulses appear full scale from 512 to 5.00 V, etc.

Leave Comment

characters left:

Related Circuits

  • New Circuits



    Popular Circuits

    AVR terminal for serial port
    Logic level relay controller
    50 MHz range frequency counter using ATtiny45 microcontroller
    Simple sine-wave generator has no low- or high-pass filters
    simplest smf automotive battery charger
    smoke detector circuit using ldr
    Field Strength Meter
    Pioneer CLD-1950
    Kapanadze 2
    Deer Repellent/ Seismic Sensors
    AD7730 digital pressure measuring circuit