Active Crossover


Posted on Nov 19, 2012

The problems that exist in common crossover networks are known. The low-pass filter causes delay in the signal. On the contrary the high-pass filter causes be pre-ahead in the signal that it in goes through from this. So, the cross-frequency are created certain problems as 1] the signals of two filters confutation 2] the change of phase between the filters influence axial 3]to axial diagram depend from the frequency. The crossover circuit try it unties many from the problems that report above and are based on research of S. Lipshitz and J. Vanderkooy that was published in the magazine JAES (Journal Audio Engineering Society).


Active Crossover
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A network crossover of linear phase it uses a low-pass department with the help of circuit of time delay and circuit of abstraction it gives in the exit signal with characteristically low-pass filter. This delay time is not constant for entire the area of frequencies, but is altered very late and mainly doesn't exist differences of phase between the signals of two outputs, neither even near in the cross-frequency. Part List R1-16=100Kohms R23-24-25-26=37.5Kohms [33K+4.7K] C12-13-20-21-22=1nF 100V MKT R2-3-4-5=56Kohms R30-31-32-33-34-35-36=10Kohms C19-23-24-30-31-32-33=47nF 100V MKT R6-27=37.5Kohms[33K+4.7K] R37-38-39-40-41-41=10Kohms C25-26-27-28-29=1nF 100V MKT R8-9-12-13-14=10Kohms R42-43-44=47Kohms C36-37=1uF 100V MKT R10-28=75Kohms (150K//150K) R45-46=47 ohms C38-39=47uF 25V R11-29=NC TR1-2-3-4=47Kohms trimmer or pot. IC1=TL071 R15=56.3Kohms C1-34-35=2.2uF 100V MKT IC2-3-4-5-6-7=TL072-NE5532 R17=12Kohms C2-3-7-8-14-15-18=47nF 100V MKT R18-19-20-21-22=10Kohms C4-5-6-9-10-11-16-17=10nF 100V MKT All the rsestors is 1/4W 1% metal film. The crossover circuit is constituted as it appears from block diagram [Fig.2] from two low-pass filters of fourth order -24db/oct, one for the line of low frequency signals and one for the high frequency. In the same frequency function also the two delay-time units, T1 (for low cross frequency F1) and T2 (for high cross frequency F2) and give him of characteristically...




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