Get Negative Rail With Cmos Gates


Posted on Apr 19, 2012    10308

Using a charge pump and oscillator, this circuit uses a 7-kHz oscillator. When the clock is high, C and D


Get Negative Rail With Cmos Gates
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are on, grounding the positive side of CI and making negative voltage available at the Vs$ terminal of U2. With C— Ci + C2, the p-p output ripple is: Converter output impedance is about 100 and maximum current is 10 mA dc.




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