The potentiometer value is not critical; any value from 1 kΩ to 100 kΩ is acceptable. If the "precision potentiometer" described earlier in this chapter has been constructed, it is recommended for use in this experiment. The actual values of the resistors are also not critical. In this experiment, a greater resistor value yields better results. The resistors do not need to be of equal value. If the sensitive voltage detector has not yet been built, it is advisable to construct one prior to this experiment. This device is simple yet very useful for testing purposes. A digital multimeter set to the "DC millivolt" (DC mV) range can be used instead of a voltage detector; however, the headphone-based voltage detector is preferred as it illustrates the ability to make precise voltage measurements without relying on expensive or advanced meter equipment. A homemade multimeter may also be used for the same reasons, although any voltmeter will suffice for this experiment.
Construct the two-resistor voltage divider circuit as shown in the schematic diagram and illustration. If the two high-value resistors are of equal value, the battery's voltage should be divided in half, with approximately 3 volts dropped across each resistor. Measure the battery voltage directly with a voltmeter, then measure the voltage drop across each resistor. An unusual observation may be noted in the voltmeter's readings. Normally, series voltage drops should equal the total applied voltage, but a significant discrepancy may be observed. This is not a violation of Kirchhoff's Voltage Law. The explanation is that connecting a voltmeter across either resistor alters the circuit, resulting in a voltage reading that differs from the scenario without the meter connected. An analogy can be drawn to an air pressure gauge used to check a pneumatic tire's pressure; when the gauge is connected, it releases some air, affecting the pressure reading. In a similar manner, voltmeters influence the voltage they measure by bypassing some current around the component whose voltage drop is being measured. Although this effect is typically negligible, it becomes pronounced in this circuit.
I recommend using your home-made multimeter for the same reason, although any voltmeter will suffice for this experiment. Build the two-resistor voltage divider circuit shown on the left of the schematic diagram and of the illustration.
If the two high-value resistors are of equal value, the battery`s voltage should be split in half, with approximately 3 volts dropped across each resistor. Measure the battery voltage directly with a voltmeter, then measure each resistor`s voltage drop. Do you notice anything unusual about the voltmeter`s readings Normally, series voltage drops add to equal the total applied voltage, but in this case you will notice a serious discrepancy.
Is Kirchhoff`s Voltage Law untrue Is this an exception to one of the most fundamental laws of electric circuits No! What is happening is this: when you connect a voltmeter across either resistor, the voltmeter itself alters the circuit so that the voltage is not the same as with no meter connected.
I like to use the analogy of an air pressure gauge used to check the pressure of a pneumatic tire. When a gauge is connected to the tire`s fill valve, it releases some air out of the tire. This affects the pressure in the tire, and so the gauge reads a slightly lower pressure than what was in the tire before the gauge was connected. In other words, the act of measuring tire pressure alters the tire`s pressure. Hopefully, though, there is so little air released from the tire during the act of measurement that the reduction in pressure is negligible.
What do you notice about the digital meter`s readings versus the analog meter`s Digital voltmeters typically have greater internal (probe-to-probe) resistance, meaning they draw less current than a comparable analog voltmeter when measuring the same voltage source. An ideal voltmeter would draw zero current from the circuit under test, and thus suffer no voltage "impact" problems.
If you happen to have two voltmeters, try this: connect one voltmeter across one resistor, and the other voltmeter across the other resistor. The voltage readings you get will add up to the total voltage this time, no matt 🔗 External reference
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